Bonjour pouvez-vous m’aider svp merci d’avance

Réponse :

Explications étape par étape

Bonjour

Établir que ce Sont des entiers négatifs :

A = 2/(2/(1/4 + 2) - 1)

A = 2/(2/(1/4 + 8/4) - 1)

A = 2/(2/(9/4) - 1)

A = 2/(2 x 4/9 - 1)

A = 2/(8/9 - 1)

A = 2/(8/9 - 9/9)

A = 2/(-1/9)

A = 2 x -9

A = -18

B = (1 - 3/2)^3 / (3/(5^3 - 101))

B = (2/2 - 3/2)^3 / (3/(125 - 101))

B = (-1/2)^3 / (3/24)

B = (-1/8) x 24/3

B = -24/8 x 1/3

B = -3 x 1/3

B = -1

C = 52 / (1/(1 + 1/(2 + 5/6) - 3))

C = 52 / (1/(1 + 1/(12/6 + 5/6) - 3))

C = 52 / (1/(1 + 1/(17/6)) - 3)

C = 52 / (1/(1 + 1 x 6/17) - 3)

C = 52 / (1/(1 + 6/17) - 3)

C = 52 / (1/(17/17 + 6/17) - 3)

C = 52 / (1/(23/17) - 3)

C = 52 / [(1 x 17/23) - 3]

C = 52 / (17/23 - 69/23)

C = 52 / (-52/23)

C = 52 x -23/52

C = -23